5x^2+170=60x

Solution for 5x^2+170=60x equation:

5x^2+170=60x

We move all terms to the left:

5x^2+170-(60x)=0

a = 5; b = -60; c = +170;
Δ = b2-4ac
Δ = -602-4·5·170
Δ = 200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{200}=\sqrt{100*2}=\sqrt{100}*\sqrt{2}=10\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-10\sqrt{2}}{2*5}=\frac{60-10\sqrt{2}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+10\sqrt{2}}{2*5}=\frac{60+10\sqrt{2}}{10}
$